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WebGem
12-10-2004, 10:05 PM
is the series sqrt(n^3)/n^3 divergent or convergent? and why?

Jenson71
12-10-2004, 10:06 PM
Haha. We're "studying" matrices.

morphius
12-10-2004, 10:11 PM
You can go to hell and die Chiefsfan5840

Valiant
12-10-2004, 10:11 PM
is the series sqrt(n^3)/n^3 divergent or convergent? and why?



it is divergent, 50% on getting it right for why..

hope that helped...

Malcor
12-10-2004, 10:35 PM
n^(3/2)/n^3

1/n^(3/2)

Converges, p>1

WebGem
12-10-2004, 10:41 PM
1/n^(3/2)
How did you get from the question to this?

Malcor
12-10-2004, 10:45 PM
sqrt(n^3)/n^3

n^(3/2)/n^3

(n^(3/2)*n^(-3/2))/(n^3*n^(-3/2))

n^0/n^(3+(-3/2))

1/n^(3/2)

seclark
12-11-2004, 07:55 AM
not real great at sipherin...i can tell you this: i was ate in '69.
hope this helps,
sec

stumppy
12-11-2004, 08:13 AM
not real great at sipherin...i can tell you this: i was ate in '69.
hope this helps,
sec


No, no, no I was 7 in '69.
You were close though.

ExtremeChief
12-11-2004, 08:33 AM
where's the other dollar??

Skip Towne
12-11-2004, 08:39 AM
Now aren't you sorry you asked?

Rain Man
12-11-2004, 04:22 PM
Sure looks convergent to me. The denominator rises faster than the numerator.

KcMizzou
12-11-2004, 05:09 PM
disergerant

Rain Man
12-11-2004, 05:15 PM
disergerant


No, I was trying to help.

chiefsfan58
12-11-2004, 06:09 PM
Sure looks convergent to me. The denominator rises faster than the numerator.

hahah, that doesn't mean anything.

1/n doesn't converge! ;)