WebGem

12-10-2004, 09:05 PM

is the series sqrt(n^3)/n^3 divergent or convergent? and why?

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WebGem

12-10-2004, 09:05 PM

is the series sqrt(n^3)/n^3 divergent or convergent? and why?

Jenson71

12-10-2004, 09:06 PM

Haha. We're "studying" matrices.

morphius

12-10-2004, 09:11 PM

You can go to hell and die Chiefsfan5840

Valiant

12-10-2004, 09:11 PM

is the series sqrt(n^3)/n^3 divergent or convergent? and why?

it is divergent, 50% on getting it right for why..

hope that helped...

it is divergent, 50% on getting it right for why..

hope that helped...

Malcor

12-10-2004, 09:35 PM

n^(3/2)/n^3

1/n^(3/2)

Converges, p>1

1/n^(3/2)

Converges, p>1

WebGem

12-10-2004, 09:41 PM

1/n^(3/2)

How did you get from the question to this?

How did you get from the question to this?

Malcor

12-10-2004, 09:45 PM

sqrt(n^3)/n^3

n^(3/2)/n^3

(n^(3/2)*n^(-3/2))/(n^3*n^(-3/2))

n^0/n^(3+(-3/2))

1/n^(3/2)

n^(3/2)/n^3

(n^(3/2)*n^(-3/2))/(n^3*n^(-3/2))

n^0/n^(3+(-3/2))

1/n^(3/2)

seclark

12-11-2004, 06:55 AM

not real great at sipherin...i can tell you this: i was ate in '69.

hope this helps,

sec

hope this helps,

sec

stumppy

12-11-2004, 07:13 AM

not real great at sipherin...i can tell you this: i was ate in '69.

hope this helps,

sec

No, no, no I was 7 in '69.

You were close though.

hope this helps,

sec

No, no, no I was 7 in '69.

You were close though.

ExtremeChief

12-11-2004, 07:33 AM

where's the other dollar??

Skip Towne

12-11-2004, 07:39 AM

Now aren't you sorry you asked?

Rain Man

12-11-2004, 03:22 PM

Sure looks convergent to me. The denominator rises faster than the numerator.

KcMizzou

12-11-2004, 04:09 PM

disergerant

Rain Man

12-11-2004, 04:15 PM

disergerant

No, I was trying to help.

No, I was trying to help.

chiefsfan58

12-11-2004, 05:09 PM

Sure looks convergent to me. The denominator rises faster than the numerator.

hahah, that doesn't mean anything.

1/n doesn't converge! ;)

hahah, that doesn't mean anything.

1/n doesn't converge! ;)

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