View Full Version : More math for you smart people...

i need answeres to this thing to prove my girlfriend wrong that the chiefsplanet crew couldn't figure it out. :)

i, however, am an idiot and I can't do it. anybody...???

3.6354

Oh wait, you haven't given the problem yet.

42, the answer to everything is 42

elvomito

03-27-2005, 11:54 PM

f'in word problems

DenverChief

03-27-2005, 11:58 PM

i need answeres to this thing to prove my girlfriend wrong that the chiefsplanet crew couldn't figure it out. :)

i, however, am an idiot and I can't do it. anybody...???

:spock:

put the :bong: down

Rausch

03-28-2005, 12:00 AM

42, the answer to everything is 42

Yup...

I'm going with-....wait...most people guess 7.

I'm going with 7...

DenverChief

03-28-2005, 12:03 AM

Yup...

I'm going with-....wait...most people guess 7.

I'm going with 7...

34 :cuss:

big nasty kcnut

03-28-2005, 12:05 AM

3/4 to the 8th power

go bowe

03-28-2005, 12:11 AM

coconuts...

DenverChief

03-28-2005, 12:13 AM

coconuts...

NUTS! terrible gay joke ;)

Rausch

03-28-2005, 12:16 AM

NUTS! terrible gay joke ;)

The gifts that keep on giving! :)

i attached a pdf...did i do something wrong?

attacment...??? why doesn't it show up?

DenverChief

03-28-2005, 12:22 AM

ah, there it is...

attachments don't work in the thread starter;)

well i got it in there...so what do you mean?

DenverChief

03-28-2005, 12:29 AM

http://www.osprey.at/_smilies/hang3.gif

Pants

03-28-2005, 12:30 AM

Hey, Dru, I don't want to steal the thunder from this thread, so this is highly off-topic (as far as it can get, lol) but did you get a new HD and if yes, could you possibly seed the Beyond the Glory file? I'm at 70% and I would really appreciate it.

DenverChief

03-28-2005, 12:30 AM

well i got it in there...so what do you mean?

in the thread starter...if you wanna post an attachment you have to start the thread and the attach it in the first post

actually i've been waiting over 2 weeks already on this guy to ship me my last hard drive. ugh.

Uhhh.... I think we're gonna need a bigger boat...

http://www.saunalahti.fi/frog1/goofs/img/jaws.jpg

Joe Seahawk

03-28-2005, 01:43 AM

.6.180

Piece of cake.. ;)

Coach

03-28-2005, 02:00 AM

E=MC˛

Braincase

03-28-2005, 05:09 AM

If I recall correctly, you can use Lagrange points to figure where to place things like telecommunications satellites. You have to figure thetotal number of satellites, and then determine their coverage area based on the distance from the object that serves as the axis and then equidistant from each other.

I could throw this one at my wife - she does crap like this in her head for fun.

keg in kc

03-28-2005, 05:13 AM

I'd help, but, well, I haven't taken a math class since Calculus my senior year in high school. I can't even remember how to add, subtract, multiply and divide without a calculator now.

Kyle401

03-28-2005, 08:41 AM

So are you in Diff. Eq. or Calc 3-4 and when is this due?

I only got up to Calc II and I forgot most of that shit a long time ago.

beavis

03-28-2005, 09:19 AM

Uhhh.... I think we're gonna need a bigger boat...

ROFL

No kidding. If I needed help with integrals, Chiefsplanet probably wouldn't be the first place I asked.

StcChief

03-28-2005, 11:17 AM

Don't remember. Use it or lose it.

wutamess

03-28-2005, 11:29 AM

Damn dude... you went to calculus on us.

WTF?

wutamess

03-28-2005, 11:30 AM

If all you and your girlfriend have to argue over is calculus problems being solved by members of CP then life must be going quite well.

:thumb:

coconuts...Put the lime in the Coke, you nut...

Bwana

03-28-2005, 11:43 AM

.453978

Now bring me a beer.

What the hell happened to the dumbasses who needed help with algebra (NTTAWWT)? Those problems I could do

Fire Me Boy!

03-28-2005, 01:45 PM

I'm the only person from my high school to drop calculus twice... I apparently didn't learn the first time.

RedNFeisty

03-28-2005, 11:27 PM

I am working on it, I will let you know.

attacment...??? why doesn't it show up?

I'm guessing that the answer to the first one is the set of functions z and y such that z + y = z'' + y'' everywhere on [0, pi/2] and which satisfy the boundary conditions. One member of that set is

z(t)=y(t)= [ exp( t ) - exp( -t ) ]

/[ exp ( pi/2 ) - exp( -pi/2 ) ]

(That's the hyperbolic sine function multiplied by a normalizing constant.)

My guess was based on generalizing the information on the following page to the case where the integrand depends on two independent functions of t:

http://mathworld.wolfram.com/Euler-LagrangeDifferentialEquation.html

My guess is just a guess. I don't know much about the Calculus of Variations and I wasn't especially careful in my calculations. ;)

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