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-   -   Science Something amazing to tell you concerning physics and motion (https://chiefsplanet.com/BB/showthread.php?t=208580)

Radar Chief 06-04-2009 10:39 AM
Quote:
Originally Posted by damaticous (Post 5816298)
Actually, from what I remember, the ball bearing in your hand would hit the ground first.

when you fire a bullet from a gun the bullet tends to arch upward a bit, so it is actually falling at a different height from the one that is dropped.

I could be wrong, but I remember reading that or seeing it on TV or something.

Otherwise, yes, they'd hit the ground at the same time.
Not quite.
A bullet starts to drop the moment it leaves the barrel. Because of that the sites are adjusted so that the barrel is actually aimed higher that what the sites indicate so that the bullet “falls” into the target at the point predicted by the sites.
The sites are also aimed slightly to the right, IIRC, because the bullet comes out spinning and will move slightly from left to right as it travels.

mikeyis4dcats. 06-04-2009 10:39 AM
Quote:
Originally Posted by orange (Post 5816340)
The bearing from the gun will land moments after the one you dropped. Unless the barrel of the gun has a length of 0. The barrel will prevent the bearing from falling until the bearing is out of the barrel.
the speed of a bullet traveling some 30 inches makes this negligible.

Baby Lee 06-04-2009 10:41 AM
Quote:
Originally Posted by MediaCenterJunkie (Post 5816309)
3 friends go out to eat.

They get the bill and it is $25, but they don't really look at it too close.

They each give the waiter a $10 bill.

The Waiter decides since he cannot split $5 evenly among 3 people he decides to pocket $2, meaning the group paid a total of $27.

So the group paid $27 ($9 each), and he has $2 in his pocket, equaling $29.

What happened to the other dollar?
They only overpay the $2. The bill was $25, but they paid $27 [with the $2 pocketed]. 30-25=5, 3 to the customer, 2 to the waiter.

You're going the wrong way with the $2, it's the over payment for the $25 bill, not additional currency outside the $9 next from each. ie, 27-2=25, not 27+2=29 [an irrelevant sum].

BigVE 06-04-2009 10:41 AM
Dinner bill: $25

3 people gave $10 each for a total of $30.

Waiter automatically pockets $2. $30-$2=$28.

He gives each of the people $1 back meaning they actually paid $9 each for a total of $27.

The extra dollar? He took it. Dang thieves.

sedated 06-04-2009 10:42 AM
Quote:
Originally Posted by MediaCenterJunkie (Post 5816309)
3 friends go out to eat.

They get the bill and it is $25, but they don't really look at it too close.

They each give the waiter a $10 bill.

The Waiter decides since he cannot split $5 evenly among 3 people he decides to pocket $2, meaning the group paid a total of $27.

So the group paid $27 ($9 each), and he has $2 in his pocket, equaling $29.

What happened to the other dollar?
There is no other dollar. The $27 ($9x3) includes the $2 the waiter took. The other $3 went back to the friends.

Am I missing something?

The second to last sentence is an illogical equation.

orange 06-04-2009 10:42 AM
Quote:
Originally Posted by Jenson71 (Post 5816350)
Count from the moment it leaves the barrel.
You can't. Because of the Heisenberg Uncertainty Principle, you can't know the bullet's exact position and its exact velocity at the same time.

Since the bullet "the moment it leaves the barrel" has a vertical velocity of 0, you can not know the instant that it actually begins to move downward. There will always be a margin of error. ;)

Buck 06-04-2009 10:43 AM
Yeah it was a trick. You guys are too smart for it.

Radar Chief 06-04-2009 10:43 AM
Quote:
Originally Posted by orange (Post 5816340)
The bearing from the gun will land moments after the one you dropped. Unless the barrel of the gun has a length of 0. The barrel will prevent the bearing from falling until the bearing is out of the barrel.
Good point, modify the theory to dropping the bearing at the same moment the other bearing leaves the rifle barrel.

Baby Lee 06-04-2009 10:43 AM
Quote:
Originally Posted by Gonzo (Post 5816345)
WTF? Wouldn't the powder charge make a difference?

Let's say Im shooting a 10 mm ball bearing with about 55 grains of rifle powder.

I'm shooting this bearing from a height of 4 ft. I drop the bearing in my other hand at the same time from 4 ft. and the hit the ground at the same time...

Ok, now I adjust the powder charge to 75 grains. I shoot from the same height, but now I have adjusted the velocity of the projectile by about 800-1,000 feet per second. This would have to be a variable somehow.
Not if you shoot on the perfect horizontal, whatever impulse you have in the horizontal direction is irrelevant to the vertical force of gravity. More grains just means you go farther faster horizontally in as you fall at the same rate to the ground.

Jenson71 06-04-2009 10:44 AM
Quote:
Originally Posted by orange (Post 5816370)
You can't. Because of the Heisenberg Uncertainty Principle, you can't know the bullet's exact position and it's exact velocity at the same time. ;)
Dammit!!

My life has no more meaning.

Baby Lee 06-04-2009 10:45 AM
Quote:
Originally Posted by T-post Tom (Post 5816312)
So if you're travelling at the speed of light in a spacecraft... and turn the headlights on...what happens? Answer me that Mr. Wisenheimer. :)
The light rays propigate forward at . . . . the speed of light.

EyePod 06-04-2009 10:45 AM
Quote:
Originally Posted by Buehler445 (Post 5816295)
You didn't know that? I learned that shit in my HS physics class. -9.8 m/s2 is stuck in my head for eternity.

WTF are they teaching you?
Posted via Mobile Device
I got accepted to college, then read the entire hitch hiker's guide to the galaxy series (i have a book that looks like a bible that contains all of the stories) instead of paying attention senior year in physics. Then I went to school for engineering, and I had to learn all the stuff that I should have learned in senior year during my freshman college year again. I was pissed that I didn't just pay attention during senior year of HS...

Simply Red 06-04-2009 10:46 AM
nerd alert!

boog out!

Buck 06-04-2009 10:47 AM
Another thing...wouldn't the mere action of observing either ball bearing affect the outcome????

orange 06-04-2009 10:49 AM
Quote:
Originally Posted by MediaCenterJunkie (Post 5816386)
Another thing...wouldn't the mere action of observing either ball bearing affect the outcome????
That's where my answer in #36 comes in.


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