Because I reset all of the clocks on daylight savings.

It all depends on where/what direction you are launching.

Surprisingly close. It's the spot behind you where, if the bullet hadn't been fired from a gun but were simply traveling at the velocity in perpetuity, the bullet would have emerged from the surface of the earth. ie, you exerted a force on the bullet to raise it from the ground to the level it is at when you fire it. That force would take the form of a vertical velocity [that peaked and turned back downwards d/t the counterforce of gravity at the level of the gun barrell] in a perpetual horizontal velocity object.

Why we still change our clocks for daylight savings time confuses me more then the realtionship between time/space.

Damn Farmers. :)

It's not moving away from the earth, it's orbiting [the earth is receding from it due to it being a ball and all, but that receding is equalled by the pull of gravity], Of course this would only work this close to the earth in a vacuum as air resistance would slow it pert quick.

You lost me.

Its orbit spreads out to a parabola, so in effect it never "returns" to its origin. (looked it up, of course).

http://upload.wikimedia.org/wikipedi...Cannon.svg.png

Now somebody explain this. Sometimes I'll post a message on this forum, and when it posts - which should refresh the page - it will show my message in position x. Then when I come back - refreshing the page again - it will show the same message in position x + y with new messages that were posted before mine but not shown.

????

You cheer for the Donkos.
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This should clear things up

http://fetchback.typepad.com/.a/6a00...1faa970b-800wi

You get that it took a force to get the bullet from the surface of the earth to the place it is in the chamber of the gun propped against your shoulder.

You get that when you fire the gun, the bullet has initally no vertical momentum and a horizontal momentum dictated by the power of the powder. And that immediately thereafter it has a vertical momentum down dictated by gravity.

Now imagine that you were on the ground and tossed a free bullet to exactly the level of the bullet in the gun, whereupon it stop midair for an instant and then would return to earth.

The negative solution represents the place behind you that a bullet with the horizontal momentum equal to that of the gunfired bullet, and a vertical momentum equal to that toss from the ground, would have to be 'tossed' for it to traverse the exact same arc as the fired bullet.

That did it. It all makes sense now. :bong:

Thanks

You need the Divide by Zero Firefox plugin....

I believe the question was how fast does it need to be fired horizontally to enter orbit(maybe the phrase was 'escape gravity').

now that would be an impressive calculation(with wind resistance please)