Quote:
Originally Posted by 'Hamas' Jenkins
This is not true, either.
Impulse equals the change in momentum.
F*∆t=m∆v
So, let's say that De'Anthony Thomas is running at his average speed during a 40, of 8.89 m/s
He weighs 80 kg.
F*∆t=80*8.89= 711.2 Newtons
Now, let's take Adrian Peterson, whose average speed during a 40 is 9.09 m/s and weighs 100 kilos
F*∆t=100*9.09=909 Newtons
Thus, you need to apply a force that is almost 30 percent greater to stop Peterson than Thomas.
But, let's say that a MLB is bearing down on both of them.
Luke Kuechly is 108 kilos and ran at an average speed of 8.73 m/s
He can deliver 943 Newtons of force.
So, what happens if both were running head on into each other?
943*∆t= 711.2; ∆t=.754
943*∆t=909; ∆t=.963
De'Anthony Thomas experience a much greater negative acceleration (deceleration) than does Peterson. Thus, his brain hits the front of his head with much greater force than Peterson, which increases the chances of injury.
Tl;Dr version? You're completely wrong.
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This is all well and good, but the two things it neglects.
1. The aforementioned effect of striking the ground, which is a much more immovable object than an opposing player.
2. How close the respective ∆ts are to the critical value for skull deceleration. If both are well above, it's not much of a difference.