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Old 01-21-2007, 06:30 PM  
Simplex3 Simplex3 is offline
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The Beryllium Thread

I'm putting this in here so that it won't hang around the top of the lounge while I cut and paste information in to post after post.

This is part of my ongoing offseaon attempt to get us ranked on the first page of some search engine(s) when nerds search for "beryllium".

Before you PM me with "Why?", the answer is simply that I am sitting around reading log files at work and cutting and pasting into this thread requires absolutely NO mental stress.

Last edited by Dartgod; 04-14-2011 at 09:18 PM..
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Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.Simplex3 would the whole thing.
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Old 04-22-2011, 12:09 AM   #6766
KurtCobain KurtCobain is offline
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Old 04-22-2011, 12:09 AM   #6767
KurtCobain KurtCobain is offline
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:10 AM   #6768
KurtCobain KurtCobain is offline
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:10 AM   #6769
KurtCobain KurtCobain is offline
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:10 AM   #6770
KurtCobain KurtCobain is offline
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[edit]Physical properties
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:11 AM   #6771
KurtCobain KurtCobain is offline
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Beryllium has exceptional flexural rigidity (Young's modulus 287 GPa) and a reasonably high melting point.
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:11 AM   #6772
KurtCobain KurtCobain is offline
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The modulus of elasticity of beryllium is approximately 50% greater than that of steel.
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:11 AM   #6773
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The combination of this modulus and a relatively low density results in an unusually fast sound conduction speed in beryllium – about 12.9 km/s at ambient conditions.
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:12 AM   #6774
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Other significant properties are high specific heat (1925 J·kg−1·K−1) and thermal conductivity (216 W·m−1·K−1), which make beryllium the metal with the best heat dissipation characteristics per unit weight.
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:12 AM   #6775
KurtCobain KurtCobain is offline
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In combination with the relatively low coefficient of linear thermal expansion (11.4×10−6 K−1), these characteristics result in a unique stability under conditions of thermal loading.[3]
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:12 AM   #6776
KurtCobain KurtCobain is offline
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[edit]Nuclear properties
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:13 AM   #6777
KurtCobain KurtCobain is offline
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Beryllium has a large scattering cross section for high-energy neutrons, thus effectively slowing the neutrons to the thermal energy range where the cross section is low (about 0.008 barn).
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:13 AM   #6778
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The predominant beryllium isotope 9Be also undergoes a (n,2n) neutron reaction to 8Be, that is, beryllium is a neutron multiplier, releasing more neutrons than it absorbs.
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:13 AM   #6779
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This nuclear reaction is:
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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Old 04-22-2011, 12:14 AM   #6780
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KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.KurtCobain is obviously part of the inner Circle.
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