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09-17-2012, 09:31 PM | #31 |
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Train B will arrive in Syracuse before Train A.
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09-18-2012, 09:25 AM | #32 |
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Sorry for the late response, but I was at a meeting that went until about 10:30 last night.
DanT, that hypergeom.dist function is the perfect tonic for what ails me. I never would've found it myself, but once I figured out how it works, it's really, really nice and easy. Love it. My numbers match austinchief's numbers, so I think I'm good. The one thing I'm still having trouble with is the number of permutations. I've taken a quick look at DanT's formulae and for some reason I'm not getting Third Eye's numbers. It may be pilot error right now since I'm not familiar with the nomenclature, so I'll work on it a little more. I may have another question later about that part. [Playful punch to the upper arm] You guys are the greatest! [/Playful punch to the upper arm]
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09-18-2012, 10:19 AM | #33 | |
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09-18-2012, 10:20 AM | #34 |
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Oh, that'll make a difference, I bet. I was seeing some really big numbers.
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09-18-2012, 12:32 PM | #35 | |||
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So most of this is assuming that we care about which white ball is in which order, right? So there are 50!/47! * 50!/43! = 5.92x10^16 combinations that are possible with 3 white orbs and 7 red orbs, assuming that each orb has a particular identity? Quote:
100!/90! = 6.29x10^19? Wait. Shouldn't this be smaller than the number I calculated above? And in this case, the number of possibilities of a 3/7 split is 50!/47!/3! *50!/47! * 50!/43! = 1.16*10^21? Wait a minute. I've got something wrong. The second number can't be bigger than the first number. What am I messing up? Quote:
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09-18-2012, 02:33 PM | #36 | ||
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WRWRR RRRRW And there are 120 ordered sequences of length 10 that have 3 white balls in them, so the total number of elementary outcomes that have 3 white balls and 7 red balls is 120 * ( 50! / 47! ) * ( 50! / 43! ) = 7.10 x 10^18 . In Excel, the formula would be = combin(10,3) * permut( 50, 3 ) * permut( 50, 43 ) . Quote:
So if we want to compute the probability of getting a "3/7 split", that would be the total number of elementary outcomes with 3 white balls in them divided by the total number of elementary outcomes, which is ( 7.10 * 10^18 )/ ( 6.29 x 10^19 ), about 11.3% . In Excel, the formula would be =HYPGEOMDIST(3,10,50,100) |
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09-18-2012, 02:45 PM | #37 | |
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Hold on a sec...typo found in the site's name: http://startrek.com Uhmmmmm...nevermind. |
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09-14-2014, 08:02 PM | #38 |
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I need help for a stats seminar. It's an online stats class, basically. The guy who teaches it is cool and definitely respects the tight teaching load so many of us in the course have, but he also gets a bit on the flowery side with his questions.
We're supposed to come up with a response to this: If light bulb manufacturers labeled their product with descriptive statistics of tested bulb life, what combination of index of center and index of spread would guide your purchase? So what the **** does "index of center" and "index of spread" mean? Yes, I've consulted the tutorials and "learning modules" we've been given. I've also Googled the terms, searched around for 2 minutes, and decided to get lazy and see if somebody here knew off the top of their heads. |
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09-14-2014, 08:05 PM | #39 | |
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09-14-2014, 08:07 PM | #40 |
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See, I thought that. Then I got mad because if that's what he meant, he made the problem 1000 times more complicated than he had to.
I'm about ready to assume that's what he means and then send something in |
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