RG III, Kap or Discount Double Check

[rtmike]

So I have all 3 in a standard IDP league.

I missed the draft so my draft was all computer picked. It's not a bad team, I thought maybe the commish may have unlocked my account to be honest. I mean shit, it even picked Seattle for my D.


Anyhoots, curious what y'all think. Which one of these (Robert Griffin III, Colin Kaepernick or Aaron Rodgers) should I keep? I usually only carry 1 QB until the bye but since I'm loaded I might just hang on to one of them.


Right now I'm leaning towards letting RG III & Kap go? Any ill/logic dis/agreeing with that?


What say you?


tia

[ChiefGator]

I would trade kap. I think Rodgers will be just as good, or better, and has less health concerns. And Kap has a huge fervor about him. Of course, earlier this week would have been better, since he has to face Seattle today.

[Chiefshrink]

No way I trade Kaep or Rodgers. I'm a huge RGIII fan as well BUT he is still not a 100% and I also see Shanny limiting his pistol plays and those plays that make him vulnerable UNTIL RG really can handle a full load which means the majority of his pts will come from his arm and not both his arm and legs. Kaep is the real deal and Rodgers is goes without saying. You could probably get a bigtime player at another position group you still feel you need depth at dangling RG out there.

[ChiefGator]

Originally Posted by Chiefshrink

No way I trade Kaep or Rodgers. I'm a huge RGIII fan as well BUT he is still not a 100% and I also see Shanny limiting his pistol plays and those plays that make him vulnerable UNTIL RG really can handle a full load which means the majority of his pts will come from his arm and not both his arm and legs. Kaep is the real deal and Rodgers is goes without saying. You could probably get a bigtime player at another position group you still feel you need depth at dangling RG out there.

I don't think anyone's biting on RG3, and you really don't need Kap and Rodgers. Rodgers is match-up proof.

You could get a WR1 and RB1 for Kap most likely.