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Old 12-24-2006, 06:27 PM   #12
mcan mcan is offline
Apr 13,1949 – Dec 15, 2011
 
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Join Date: Aug 2000
Location: Kansas City, MO
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Quote:
Originally Posted by RedBull
Apply division tie breaker to eliminate all but the highest ranked club in each division prior to proceeding to step 2. The original seeding within a division upon application of the division tie breaker remains the same for all subsequent applications of the procedure that are necessary to identify the two Wild-Card participants.
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This is the important thing. They want to make sure that the division standings remain intact in the conference standings. Here is how it stacks up right now.


AFC CONFERENCE
1 San Diego W 12-2
2 Baltimore N 12-3
3 Indianapolis S 11-4
4 New England E 11-4
5 Denver W 8-6
6 Cincinnati N 8-6
7 N.Y. Jets E 8-6
8 Tennessee S 8-7 <-- Example (conf 5-6)
9 Kansas City W 8-7 <-- Example (conf 4-7)
10 Jacksonville S 8-7 <-- Example (conf 5-6)
11 Buffalo E 7-8
12 Pittsburgh N 7-8
13 Miami E 6-8
14 Houston S 5-10
15 Cleveland N 4-11
16 Oakland W 2-13


Jacksonville's conference record is better than ours, but divison matters first. Tennessee is above Jacksonville in the South because they have a better division record, so the next tiebreaker happens exclusively between KC and Tenn, they win that tiebreaker. This exact scenerio can happen if KC and Denver end up tied in the West. We win the tiebreaker over them and lose a tiebreaker to somebody else and get a 6 seed while Denver stays home.
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