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Old 08-03-2011, 01:52 AM   #11
Ming the Merciless Ming the Merciless is offline
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18.41 rolls to be near 2.51 standard deviations--assuming a normal distribution


2.51 std deviations = ~.005 (half of a percent)

I am reading the question as this: how many times would I have to roll the dice to be at 2.51 std devs for not seeing that number come up..


so

.75% ^ x = .005


18.41 rolls in a row without N number showing up




disclaimer: im drunk , tired and going to bed LOL
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