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Old 07-23-2013, 09:23 PM   Topic Starter
Fat Elvis Fat Elvis is offline
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A question for the engineers....

I have a question about egg drop stuff....

An egg typically weighs 55 grams.

It takes 25 Newtons to break an egg.

If you drop an egg from 25 ft, the egg will be travelling at ~40 ft/sec (12.2 m/sec) or roughly 27 mph when it hits the ground.

Assuming no use of a parachute or whatever to decrease the rate of fall, how much force needs to be "absorbed"/redirected or whatever to keep the egg from breaking?

How many Newtons (I'm not really sure what that is other than it is a unit of force where it is the amount needed to accelerate 1 kilogram of mass at the rate of 1 metre per second squared) would be exerted on the egg from a drop from that height?

I'm stumped.
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