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Old 10-11-2012, 06:02 PM   #1
DrunkBassGuitar DrunkBassGuitar is offline
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Originally Posted by bench_cassel View Post
Then your saying the answer 50% is correct, because the answer 25% is correct as is the other answer 25%. Therefore you're saying 3/4 answers are correct.
But you don't have a 50% chance of picking B, you only have a 25% chance.

So therefore there is no solution.
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Old 10-11-2012, 06:08 PM   #2
bench_cassel bench_cassel is offline
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Originally Posted by DrunkBassGuitar View Post
But you don't have a 50% chance of picking B, you only have a 25% chance.

So therefore there is no solution.
uh the guy implied 25% was the correct answer. and 25% is on there twice therefore he thought the answer should be 50% ----25% is on there twice which would make the answer 50%. but then your stating 3/4 answers is correct which is incorrect. There is no solution...as far as I can see
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Old 10-11-2012, 06:11 PM   #3
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Quote:
Originally Posted by bench_cassel View Post
uh the guy implied 25% was the correct answer. and 25% is on there twice therefore he thought the answer should be 50% ----25% is on there twice which would make the answer 50%. but then your stating 3/4 answers is correct which is incorrect. There is no solution...as far as I can see
This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing
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Old 10-11-2012, 06:16 PM   #4
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Originally Posted by cyborgtable View Post
This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing
i see what you're saying but the answer is not A or D the answer is B. therefore you don't have a 50% chance at random.
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Old 10-11-2012, 06:20 PM   #5
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Originally Posted by bench_cassel View Post
i see what you're saying but the answer is not A or D the answer is B. therefore you don't have a 50% chance at random.
The answer is A and D, both answers are correct and thus 50% is the solution.
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Old 10-11-2012, 06:21 PM   #6
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Originally Posted by cyborgtable View Post
The answer is A and D, both answers are correct and thus 50% is the solution.
then your saying 50% is correct and A and D's answers of 25% are not correct. If you don't understand that then I'm done.
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Old 10-11-2012, 06:21 PM   #7
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Originally Posted by cyborgtable View Post
The answer is A and D, both answers are correct and thus 50% is the solution.
your logic is off bruh
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Old 10-11-2012, 06:23 PM   #8
cyborgtable cyborgtable is offline
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your logic is off bruh
If I didn't cheat I would agree. This was an extra credit problem on a probability and statistics course I'm currently in
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Old 10-11-2012, 06:17 PM   #9
DrunkBassGuitar DrunkBassGuitar is offline
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Quote:
Originally Posted by cyborgtable View Post
This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing
In that case yes. But in the question posed, only one answer is 50%. That means you only have a 1/4 chance of randomly (assuming random means answers A,B,C and D are equally likely to get picked) picking answer B. Since you only have a 25% chance of picking B, B cannot be correct.

It's a paradox, which means it has no solution.

The only way you can make this question solvable is to say that random means something else, for instance a random distribution where you have a 10% chance of picking A, a 20% chance of B, a 60% chance of picking C and a 15% chance of picking D. In that scenario, C would be the correct answer. But a situation like that is the only way this question is solvable.
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