Food for thought - A, B, C, or D?

[cyborgtable]

Originally Posted by bench_cassel

uh the guy implied 25% was the correct answer. and 25% is on there twice therefore he thought the answer should be 50% ----25% is on there twice which would make the answer 50%. but then your stating 3/4 answers is correct which is incorrect. There is no solution...as far as I can see

This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing

[bench_cassel]

Originally Posted by cyborgtable

This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing

i see what you're saying but the answer is not A or D the answer is B. therefore you don't have a 50% chance at random.

[cyborgtable]

Originally Posted by bench_cassel

i see what you're saying but the answer is not A or D the answer is B. therefore you don't have a 50% chance at random.

The answer is A and D, both answers are correct and thus 50% is the solution.

[bench_cassel]

Originally Posted by cyborgtable

The answer is A and D, both answers are correct and thus 50% is the solution.

then your saying 50% is correct and A and D's answers of 25% are not correct. If you don't understand that then I'm done.

[Bump]

Originally Posted by cyborgtable

The answer is A and D, both answers are correct and thus 50% is the solution.

your logic is off bruh

[cyborgtable]

Originally Posted by Bump

your logic is off bruh

If I didn't cheat I would agree. This was an extra credit problem on a probability and statistics course I'm currently in

[bench_cassel]

Originally Posted by cyborgtable

If I didn't cheat I would agree. This was an extra credit problem on a probability and statistics course I'm currently in

then your professor isn't analyzing it critically. if so i'm open for explanations.

[Bump]

Originally Posted by cyborgtable

If I didn't cheat I would agree. This was an extra credit problem on a probability and statistics course I'm currently in

and 50% is the correct answer your professor/teacher gave you? What school is this?

[cyborgtable]

Originally Posted by Bump

and 50% is the correct answer your professor/teacher gave you? What school is this?

University of Louisville, as well as my number theory professor at elizabethtown community college

[DrunkBassGuitar]

Originally Posted by cyborgtable

This is asking a question, not asking to pick the answer at random. Think of it this way, if you were taking a multiple choice history test and 2 of the solutions were the same and correct. If you didn't know and just guessed you would have a 50% chance of answering the question correct. This is the same thing

In that case yes. But in the question posed, only one answer is 50%. That means you only have a 1/4 chance of randomly (assuming random means answers A,B,C and D are equally likely to get picked) picking answer B. Since you only have a 25% chance of picking B, B cannot be correct.

It's a paradox, which means it has no solution.

The only way you can make this question solvable is to say that random means something else, for instance a random distribution where you have a 10% chance of picking A, a 20% chance of B, a 60% chance of picking C and a 15% chance of picking D. In that scenario, C would be the correct answer. But a situation like that is the only way this question is solvable.