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Old 08-28-2009, 02:40 PM   #1
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Originally Posted by GoChiefs View Post
Cassel is standing on the 47 and the ball hits a receiver at the 7-yard line.

When you compensate for the angle...
i dont think you actually compensate for angle
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Old 08-28-2009, 02:46 PM   #2
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Originally Posted by JASONSAUTO View Post
i dont think you actually compensate for angle
Sure you do. A football field is 53 1/3 yards wide.

A 10-yard completion to the middle of the field is a much easier throw than a 10-yard out to the sideline. The sideline throw travels a much greater distance...
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Old 08-28-2009, 03:11 PM   #3
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Originally Posted by GoChiefs View Post
Sure you do. A football field is 53 1/3 yards wide.

A 10-yard completion to the middle of the field is a much easier throw than a 10-yard out to the sideline. The sideline throw travels a much greater distance...
I can't believe that was questioned.
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Old 08-28-2009, 03:17 PM   #4
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I can't believe that was questioned.
so you would say that ball was a 50 yard throw?
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Old 08-28-2009, 03:19 PM   #5
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Originally Posted by JASONSAUTO View Post
so you would say that ball was a 50 yard throw?
I haven't followed the thread.

I just noticed that you don't understand basic math.
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Old 08-28-2009, 03:23 PM   #6
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Originally Posted by OnTheWarpath58 View Post
I haven't followed the thread.

I just noticed that you don't understand basic math.
you ****ing idiot i understand math. next time you should follow the thread before saying stupid shit
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Old 08-28-2009, 03:11 PM   #7
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Originally Posted by GoChiefs View Post
Sure you do. A football field is 53 1/3 yards wide.

A 10-yard completion to the middle of the field is a much easier throw than a 10-yard out to the sideline. The sideline throw travels a much greater distance...

Yes, indeed, we can agree about that. Anyone want a lesson on "hypotenuse" measure??
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Old 08-28-2009, 03:15 PM   #8
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Yes, indeed, we can agree about that. Anyone want a lesson on "hypotenuse" measure??
Well let's see....47 yards on one side, 27 yards on the other (Cassel is in the middle of the field), what's the other side come out to?

Once we know that we can determine the velocity of the throw and convert to mph and compare to MLB...

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Old 08-28-2009, 03:32 PM   #9
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Well let's see....47 yards on one side, 27 yards on the other (Cassel is in the middle of the field), what's the other side come out to?

Once we know that we can determine the velocity of the throw and convert to mph and compare to MLB...


The pass was 54.2 yards


27 x 27 = 729
47 x 47 = 2209

square root of sum of 729 and 2209 is 54.20332


Right triangle hypotenuse is the square root of the sum of the squared sides of the right angle.
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Old 08-28-2009, 03:41 PM   #10
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Originally Posted by TFG View Post
The pass was 54.2 yards


27 x 27 = 729
47 x 47 = 2209

square root of sum of 729 and 2209 is 54.20332


Right triangle hypotenuse is the square root of the sum of the squared sides of the right angle.
I should have said 40, not 47. Anyway, CP math lesson for the day.
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Old 08-28-2009, 03:45 PM   #11
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I should have said 40, not 47. Anyway, CP math lesson for the day.

That would make the throw 47.2 yards in the air.
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Old 08-28-2009, 03:18 PM   #12
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Originally Posted by GoChiefs View Post
Sure you do. A football field is 53 1/3 yards wide.

A 10-yard completion to the middle of the field is a much easier throw than a 10-yard out to the sideline. The sideline throw travels a much greater distance...
i get that. but is that how the nfl or anyone else measures the throw?
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Old 08-28-2009, 03:20 PM   #13
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Originally Posted by JASONSAUTO View Post
i get that. but is that how the nfl or anyone else measures the throw?
no
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Old 08-28-2009, 03:22 PM   #14
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Originally Posted by JASONSAUTO View Post
i get that. but is that how the nfl or anyone else measures the throw?
Not for statistical purposes.

But for real-world purposes, sure.
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Old 08-28-2009, 03:24 PM   #15
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Not for statistical purposes.
thank you. now that was a 40 yard throw in the air. from the 47 to the 7
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